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Syntax: $ operator #28

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alcides opened this issue Mar 2, 2024 · 0 comments
Open

Syntax: $ operator #28

alcides opened this issue Mar 2, 2024 · 0 comments
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enhancement New feature or request good first issue Good for newcomers help wanted Extra attention is needed

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@alcides
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alcides commented Mar 2, 2024

Haskell supports f $ g a as a shorthand for f (g a).

The way this can be implemented is adding to the syntax the $ operator with the right precedence.

In Haskell, $ has the following type:

($) :: (a -> b) -> a -> b

So this depends on Polymorphism.
@alcides alcides added the good first issue Good for newcomers label Mar 2, 2024
@alcides alcides changed the title $ operator. $ operator Mar 2, 2024
@alcides alcides added enhancement New feature or request help wanted Extra attention is needed labels Mar 2, 2024
@alcides alcides changed the title $ operator Syntax: $ operator Mar 6, 2024
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enhancement New feature or request good first issue Good for newcomers help wanted Extra attention is needed
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