007MoreFrequentItem.py

# Create a function named more_frequent_item that has three parameters named lst, item1, and item2.
# Return either item1 or item2 depending on which item appears more often in lst.
# If the two items appear the same number of times, return item1.

def more_frequent_item(lst, item1, item2):
  if(lst.count(item1) > lst.count(item2) or lst.count(item1) == lst.count(item2)):
    return item1
  else:
    return item2

print(more_frequent_item([2, 3, 3, 2, 3, 2, 3, 2, 3], 2, 3))