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310: Update learning_rate_scheduler.md r=eviatarbach a=eviatarbach

Standard deviation in the example is 5, so variance should be 25.

Co-authored-by: Eviatar Bach <[email protected]>
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bors[bot] and eviatarbach committed Jul 7, 2023
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We demonstrate the behaviour of different learning rate schedulers through solution of a nonlinear inverse problem.

In this example we have a model that produces the exponential of a sinusoid ``f(A, v) = \exp(A \sin(t) + v), \forall t \in [0,2\pi]``. Given an initial guess of the parameters as ``A^* \sim \mathcal{N}(2,1)`` and ``v^* \sim \mathcal{N}(0,5)``, the inverse problem is to estimate the parameters from a noisy observation of only the maximum and mean value of the true model output.
In this example we have a model that produces the exponential of a sinusoid ``f(A, v) = \exp(A \sin(t) + v), \forall t \in [0,2\pi]``. Given an initial guess of the parameters as ``A^* \sim \mathcal{N}(2,1)`` and ``v^* \sim \mathcal{N}(0,25)``, the inverse problem is to estimate the parameters from a noisy observation of only the maximum and mean value of the true model output.

We shall compare the following configurations of implemented schedulers.
1. Fixed, long timestep `DefaultScheduler(0.5)` - orange
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